A Poster Can Have A Maximum Perimeter Of 42 Inches Long

I hope this helped a bit! How would you figure the area of a pentagon? And of course, if that distance is 21 feet, this distance is also going to be 21 feet. Im bored, school is boring(7 votes). Is there another way of doing this? How do you find the area of a cricle(4 votes). This process is called taking the square root. And what's that going to be equal to? What is the length of one side of the square? And 78 minus 42-- I don't want to make a careless mistake-- 78 minus 42 is going to get me to 36. A poster can have a maximum perimeter of 42 inches max 33. Step-by-step explanation: We have, A page should have perimeter of 42 inches. This is what we needed the two widths to add up to-- plus 42. The area of a square is 144 square centimeters.

1. A poster can have a maximum perimeter of 42 inches
2. A poster can have a maximum perimeter of 42 inches 6 pockets
3. A poster can have a maximum perimeter of 42 inches in length
4. A poster can have a maximum perimeter of 42 inches max 33
5. A poster can have a maximum perimeter of 42 inchem.org

A Poster Can Have A Maximum Perimeter Of 42 Inches

So let's draw what it might look like. The printing area within the page would be determined by top and bottom margins of 1 inch from each side, and the left and right margins of 1. How to calculate depth? Still have questions? Afterwards, 18/2 = 9. And this one up here must also be 18. So what are two distances, or what are two numbers that I can add together to get to 36? Grade 11 · 2022-09-17. What is the width of Mike's dog pen? The formula is pi times the radius squared. And, ∴ Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long. A poster can have a maximum perimeter of 42 inches to feet. So let's at least subtract these two orange lengths, the two 21 feet, from the 78 feet. And we can verify that. Point your camera at the QR code to download Gauthmath.

A Poster Can Have A Maximum Perimeter Of 42 Inches 6 Pockets

Provide step-by-step explanations. Crop a question and search for answer. And you add the two lengths, plus 21 plus 21. Depth is not something that you would calculate so much as you would just measure it. Edit: Ask me if you need help:)(3 votes). Gauthmath helper for Chrome. A poster can have a maximum perimeter of 42 inches - Gauthmath. The area of a square is the side length times itself. Let's do 78 minus 21 minus 21. Which is, of course, equal to-- 36 plus 42 is equal to 78, which is the perimeter.

A Poster Can Have A Maximum Perimeter Of 42 Inches In Length

Check the full answer on App Gauthmath. So let's say that this is the dog pen right over here. And we know how we figure out the perimeter. First, you multiply the width by 2. Next, you subtract 8 from the perimeter which is 26, and the difference is 18. Let's assume width of the page be x inches and its length be y inches So, Perimeter = 42 inches.

A Poster Can Have A Maximum Perimeter Of 42 Inches Max 33

And then we figure out how much length essentially these two widths have to make up. So this is equal to 36. Now, we know something else. And let's remind ourselves what 36 feet is. A poster can have a maximum perimeter of 42 inches in length. Let's find: =, for area to be maximum = 0. The area is given in square centimeters, so the side length is in centimeters. So we need to figure out the width. Sal figures out the width of a dog pen. So it might look something like this. So this distance right over here is 21 feet. Want to join the conversation?

A Poster Can Have A Maximum Perimeter Of 42 Inchem.Org

So we need to find what positive number times itself would give 144. And you are left with 36, which is exactly what we got here. I'm in 4rth grade and I'm trying to figure it out... '(5 votes). Created by Sal Khan.

'How would you find the perimeter of a circle? ' This means that 9 is the length. And if we add them together, we get to 36. So that's 78 minus 42. And the width would be this length-- or this width, I should say-- this width, which is going to be the same thing as that width right over here. Well, we know that 18 plus 18 is equal to 36. Mike built a rectangular dog pen that is 21 feet long and has a perimeter of 78 feet. So let's think about. Good Question ( 66). Area & perimeter word problem: dog pen (video. Now, they also tell us that the perimeter is 78 feet. Width of printed area = x-3 & length of printed area = y-2: area =. This positive number is 12. Try adding all of these up together.